nilai x yang memenuhi persamaan[tex] 4_{log} (2x+1) . (2x+1)_{log} (2x-2) = 2 [/tex]
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nilai x yang memenuhi persamaan[tex]
4_{log} (2x+1) . (2x+1)_{log} (2x-2) = 2 [/tex]
4_{log} (2x+1) . (2x+1)_{log} (2x-2) = 2 [/tex]
1 Jawaban
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1. Jawaban arindaaristiani
⁴log(2x+1) . [tex] ^{(2x+1)} log(2x-2)[/tex] = 2
⁴log(2x-2) = ⁴log4²
2x - 2 = 16
2x = 16 + 2
2x = 18
x = 9