bantu dong please!!! Gas oksigen pada suhu 27oC memiliki volume 30 liter dan tekanan  105 Pa. Tentukan volume gas oksigen tersebut jika tekanannya dibuat menjad

[tex]\displaystyle T_1=300\,\text{K}\\V_1=30\,\text{L}\\P_1=10^5\,\text{Pa}\\P_2=2,5\cdot10^5\,\text{Pa}\\T_2=400\,\text{K}\\\\V_2=?\\\\\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\\\frac{10^5\cdot30}{300}=\frac{2,5\cdot10^5V_2}{400}\\\frac{30}{3}=\frac{2,5V_2}{4}\\\frac{30}{3}=\frac{5V_2}{8}\\2=\frac{V_2}{8}\\2\cdot8=V_2\\\boxed{\boxed{16\,\text{L}=V_2}}[/tex]

Rumus boyle-lussac
P1 x V1 ÷ T1 = P2 x V2 ÷ T2
10^5 x 30 ÷ 300 = 2,5 x 10^5 x V2 ÷ 400
V2 = (10^5 x 30 x 400) ÷ (300 x 2,5 x 10^5)
V2 = 16 Liter