sebanyak x mol koh dimasukkan kedalam 100 ML H2SO4 0,2.larutan ini ternyata membutuhkan 1 gr NAOH agar netral . Nilai X tersebut adalah.... (MR NaOH = 40)

[tex]\displaystyle \underset{12,5\,\text{mmol}}{\underset{n}{\text{H}_2\text{SO}_4_{(aq)}}}+\underset{25\,\text{mmol}}{\underset{25\,\text{mmol}}{2\text{NaOH}_{(aq)}}}\to\text{Na}_2\text{SO}_4_{(aq)}+2\text{H}_2\text{O}_{(l)}\\\\\\n-12,5=0\\n=12,5\,\text{mmol}[/tex]

[tex]\displaystyle\underset{n}{ \underset{x}{\underset{20\,\text{mmol}}{\text{H}_2\text{SO}_4_{(aq)}}}}+\underset{x}{\underset{x}{2\text{KOH}_{(aq)}}}\to\text{K}_2\text{SO}_4_{(aq)}+2\text{H}_2\text{O}_{(l)}\\\\\\20-x=n\\20-x=12,5\\x=7,5\,\text{mmol}\\\boxed{\boxed{x=0,0075\,\text{mol}}}[/tex]