Tolong dibantu dan dijawab nomer 22. Makasih sebelumnya.

(-1 ... 4) + (4 ... -5) = (2 ... -1) (2p ..... 1)
(-2 .. 3) .. (-3 .. 2) ... (-4 ... 3) (1 .. q + 1)

(3 ... -1) = (4p - 1 ......... 2 - 1(q + 1))
(-5 .. 5) .. (-8p + 3 ... -4 + 3(q + 1))

Baris 1 kolom 1
3 = 4p - 1 => 4 = 4p => p = 1

Baris 1 kolom 2
-1 = 2 - 1(q + 1) => -1 = 2 - q - 1 => -1 = 1 - q => q = 2

p + q = 1 + 2 = 3