KUIS MATEMATIKA Kode: 01-1-3

Materi: Geometri Analitik

Jawaban D

Perhatikan gambar

Luas AEGF = 36 cm^2
s^2 = 36
s = 6 => AG = GF

Luas GHLB = 25 cm^2
s^2 = 25
s = 5 => GB = GH

HF = GF - GH = 6 - 5 = 1 => HF = FJ = 1 cm
Luas HFJI = 1^2 = 1 cm^2 =============> luas persegi terkecil

EJ = EF + FJ = 6 + 1 = 7 cm => EJ = ED = 7 cm
Luas EDKJ = 7^2 = 49 cm^2 ===========> luas persegi terbesar

Jadi perbandingan luas persegi terkecil dan terbesarnya 1 : 49

SKETSA GAMBAR