Tolong bantu jawab yaa

Jawaban dan pembahasan terlampir

[tex]\displaystyle \lim_{x\to2}\frac{x^2-4}{x^3+1}=\frac{2^2-4}{2^3+1}\\\lim_{x\to2}\frac{x^2-4}{x^3+1}=\frac{4-4}{8+1}\\\boxed{\boxed{\lim_{x\to2}\frac{x^2-4}{x^3+1}=0}}[/tex]