ten invers dari (fog)^-1(x) jika dik... f(x) = 2x - 1 g(x) = 3x + 5

(fog)(x) = f{g(x)}
y = 2g(x) - 1
y = 2(3x + 5) - 1
y = 6x + 10 - 1
y = 6x + 9
6x = y - 9
x = (y - 9)/6

(fog)`¹(x) = (x - 9)/6

semoga berguna +_+

Saya coba bantu yah !

Penyelesaian :
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Diket : f (x) = 2x - 1 , g (x) = 3x + 5

Pertama , kita cari dulu (fog) (x) lalu kemudian baru di invers kan :

(fog) (x) = f [g (x)]
= f (3x + 5)
= 2 (3x + 5) - 1
= 6x + 10 - 1
= 6x + 9

(fog) (x) = 6x + 9
Misal :
y = (fog) (x)

(fog) (x) = 6x + 9
y = 6x + 9
y - 9 = 6x
6x = y - 9
x = (y - 9) / 6
(fog)⁻¹ (x) = (x - 9) / 6

Maka , (fog)⁻ ¹ (x) adalah (x - 9) / 6

Semoga bisa membantu ya