jika f (x) = 3x²-10/ x + 6, maka f (0) + 6 F'(0) =

f (0) = -10 / 6 = -5/3
f'(x) = 6x (x+6) - (3x^2 - 10) . 1 / (x+6)^2
f'(0) = 10 / 36 = 5 / 18

Maka : f(0) + 6f'(0) = -5/3 + 5/3 = 0 -> Jawab

Mapel : Matematika
Kelas : XI SMA
Bab : Differensial

Pembahasan :
f(0) = [3(0)² - 10]/(0 + 6)
f(0) = -10/6 = -5/3

f'(0) = [3(0)² +36(0) + 10]/(0 + 6)²
f'(0) = 10/36 = 5/18

Maka...
f(0) + 6f'(0)
= -5/3 + 6(5/18)
= -5/3 + 5/3
= 0