Tolong bantu saya jawab no 2 a-e

[ a ] C2H5OH + 3 O2 → 2 CO2 + 3 H2O

misal :
[a] C2H5OH + [b] O2 → [c] CO2 + [d] H2O

C => 2a = c
O => 2b + a = 2c + d
H => 6a = 2d <=> d = 3a

misal : a = 1
c = 2a = 2(1) = 2
d = 3a = 3(1) = 3

2b + a = 2c + d
b = ( 2c + d - a ) / 2
b = ( 2(2) + 3 - a ) / 2 = ౩

Jadi :
C2H5OH + 3 O2 → 2 CO2 + 3 H2O

[ b ] H2S + 2 FeCl3 → 2 FeCl2 + S + 2 HCl

misal :
[a] H2S + [b] FeCl3 → [c] FeCl2 + [d] S + [e] HCl

S => a = d
Fe => b = c
Cl => 3b = 2c + e <=> 3b = 2b + e <=> b = e
H => 2a = e

misal : a = 1
d = a = 1
e = 2a = 2(1) = 2
c = b = e = 2

Jadi :
H2S + 2 FeCl3 → 2 FeCl2 + S + 2 HCl

[ c ] 3 Cl2 + 6 KOH → 5 KCl + KClO3 + 3 H2O

misal :
[a] Cl2 + [b] KOH → [c] KCl + [d] KClO3 + [e] H2O

Cl => 2a = c + d
K => b = c + d <=> 2a = b
O => b = 3d + e
H => b = 2e <=> 2a = 2e <=> a = e

mis : a = 3
b = 2a = 2(3) = 6
a = e = 3

b = 3d + e
d = (b - e) / 3 = (6 - 3) / 3 = 1

b = c + d
c = b - d = 6 - 1 = 5

Jadi :
3 Cl2 + 6 KOH → 5 KCl + KClO3 + 3 H2O

[ d ] 3 Cu + 8 HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O

misal :
[a] Cu + [b] HNO3 → [c] Cu(NO3)2 + [d] NO + [e] H2O

Cu => a = c
N => b = 2c + d
O => 3b = 6c + d + e
H => b = 2e

misal : a = 3
c = a = 3

3b = 6c + d + e
3(2c + d) = 6c + d + e
6c + 3d = 6c + d + e
2d = e

3b = 6c + d + e
3(2e) = 6c + d + e
5e = 6c + d
5(2d) = 6c + d
9d = 6c
d = ⅔ c = 2

b = 2c + d = 2(3) + 2 = 8

e = 2d = 2(2) = 4

Jadi :
3 Cu + 8 HNO3 → 3 Cu(NO3)2 + 2 NO + 4 H2O

[ e ] Br2 + 2 NaOH → NaBr + NaBrO + H2O

misal :
[a] Br2 + [b] NaOH → [c] NaBr + [d] NaBrO + [e] H2O

Br => 2a = c + d
Na => b = c + d <=> b = 2a
O => b = d + e
H => b = 2e <=> e = a

misal : a = 1
b = 2(a) = 2(1) = 2
e = a = 1
b = d + e <=> d = b - e = 2 - 1 = 1
b = c + d <=> c = b - d = 2 - 1 = 1

Jadi :
Br2 + 2 NaOH → NaBr + NaBrO + H2O