[tex] \int\limits {x}^2 \, dx [/tex]

Rumus umum integral fungsi:
∫ x^n dx
= 1/(n+1) x^(n+1) + C

maka:
∫ x² dx
= 1/(2+1) x^(2+1) + C
= 1/3 x³ + C

Jadiin sebagai solusi terbaik ya :3

[tex]\int\limits {x}^2 \, dx[/tex]

[tex]= \frac{1}{2+1} x^{(2+1)} + C[/tex]

[tex]= \frac{1}{3} x^{3} + C[/tex]

NB :
Rumus integral fungsi :
[tex] \int\limits {ax^{n}} \, dx = \frac{a}{n+1}x^{n+1} + C [/tex]