Jika diketahui data sbg berikut : C(s) + O(g) -> CO2 ΔH = -393,5 kj/mol H2(g) + 1/2O2(g) -> H2O(l) ΔH = -285.8 kj/mol CH4 (g) + 2O2 (g) -> CO2(g) +
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Pertanyaan
Jika diketahui data sbg berikut :
C(s) + O(g) -> CO2 ΔH = -393,5 kj/mol
H2(g) + 1/2O2(g) -> H2O(l) ΔH = -285.8 kj/mol
CH4 (g) + 2O2 (g) -> CO2(g) + 2H2O(l) ΔH = -890.3 kj/mol
Maka ΔH° reaksi C(grafite) + 2H2(g) -> CH4(g)?
C(s) + O(g) -> CO2 ΔH = -393,5 kj/mol
H2(g) + 1/2O2(g) -> H2O(l) ΔH = -285.8 kj/mol
CH4 (g) + 2O2 (g) -> CO2(g) + 2H2O(l) ΔH = -890.3 kj/mol
Maka ΔH° reaksi C(grafite) + 2H2(g) -> CH4(g)?
1 Jawaban
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1. Jawaban rikuta7
C(s) + O(g) => CO2 ΔH = -393,5 kj/mol ( ×1 )
H2(g) + 1/2O2(g) => H2O(l) ΔH = -285.8 kj/mol ( × 1 )
CH4 (g) + 2O2 (g) => CO2(g) + 2H2O(l) ΔH = -890.3 kj/mol (×-1)
C(s) + O(g) => CO2
2 H2(g) + O2(g) => 2 H2O(l)
CO2(g) + 2 H2O(l) => CH4 (g) + 2 O2 (g)
------------------------------------------------------ +
C(s) + 2H2(g) => CH4(g)
∆H = (-393,5 kJ/mol) + (-295,8 kJ/mol) + 890,3 kJ/mol
∆H = +201 kJ/mol