Matematika

Pertanyaan

Met mlm kk,tolong bantuin kk,, seklian caranya ,,mksh sblmnya
Met mlm kk,tolong bantuin kk,, seklian caranya ,,mksh sblmnya

1 Jawaban

  • 1) a^b = 2^15 - 2^14
    a^b = 2^1 . 2^14 - 2^14 ======> misal 2^14 = x
    a^b = 2x - x
    a^b = x
    a^b = 2^14 = (2^2)^7 = 4^7
    Karena FPB (a,b) = 1 maka a^b = 4^7 => a = 4 dan b = 7
    (Jika a^b = 2^14 maka a = 2 dan b = 14 tetapi FPB nya = 2)
    a + b = 4 + 7 = 11

    2) x^2 - (2a^10 - b^9 - 3c)x + (4a^10.b - 2b^10 - 6bc) = 0
    1/x1 + 1/x2 = 1/10
    (x1 + x2)/(x1.x2) = 1/10
    (-b/a) / (c/a) = 1/10
    -b/c = 1/10
    -(-(2a^10 - b^9 - 3c)) / (4a^10.b - 2b^10 - 6bc) = 1/10
    (2a^10 - b^9 - 3c) / 2b(2a^10 - b^9 - 3c) = 1/10
    1/(2b) = 1/10
    2b = 10
    b = 5