Matematika

Pertanyaan

jika f(x) = 8x^2 / (4-x)^2 maka nilai f'(2) / f(2) =...

1 Jawaban

  • f(x) = (8x^2) / (4 - x)^2 => f(2) = (8.2^2) / (4 - 2)^2 = 8(4) / 2^2 = 8
    f(x) = u/v
    u = 8x^2 => u' = 16x
    v = (4 - x)^2 => v' = 2(4 - x) . -1 = 2x - 8
    f'(x) = (u' v - v' u) / v^2
    = (16x (4 - x)^2 - (2x - 8)(8x^2)) / (4 - x)^4
    f'(2) = (16(2) (4 - 2)^2 - (2(2) - 8) (8 (2)^2)) / (4 - 2)^4
    = (32 (4) - (-4) (32)) / 2^4
    = (128 + 128) / 16
    = 256/16
    = 16

    f'(2) / f(2) = 16 /8 = 2

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