Cari Dxy = y= (3x²+5)²(x³-11)⁴

Materi: Diferensial

Turunkan dengan aturan hasil kali, pngkat, dan rantai
u = (3x^2 + 5)^2 berarti u' = 2(3x^2+5)(6x) = 12x(3x^2 + 5)
v = (x^3-11)^4 berarti v' = 4(x^3-11)^3(3x^2) = 12x^2 (x^3 - 11)
shg
dy/dx = u'v+uv' =
12x(3x^2+5)×(x^3-11)^4 + (3x^2+5)^2×(12x^2(x^3-+1))