Matematika

Pertanyaan

y = cos(x²), cari d³y/dx³

1 Jawaban

  • y = cos x²

    dy/dx = - sin x² . 2x = -2x sin x² = u . v
    u = -2x => u' = -2
    v = sin x² => v' = cos x² . 2x = 2x cos x²

    d²y/dx² = u' v + v' u
    = -2 sin x² + 2x cos x² . -2x
    = -2 sin x² + (-4x²) cos x²
    u = -4x² => u' = -8x
    v = cos x² => v' = - sin x² . 2x = -2x sin x²

    d³y/dx³ = -2 cos x² . 2x + u' v + v' u
    = -4x cos x² + (-8x) cos x² + (-2x sin x²) . -4x²
    = -12x cos x² + 8x³ sin x²

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