jumlah mol dari 64 gram CH4 ( Ar C=12, C= 1 ) jawbannya

[tex]\displaystyle STOIKIOMETRI \\ \\ n = \frac{gr}{Mr} = \frac{64}{16} = 4 \ mol \ -\ \textgreater \ Jawab [/tex]

Mr CH4 = Ar C + 4 Ar H
= 12 + 4(1) = 16

m CH4 = 64 gram

n CH4 = m / Mr
n CH4 = 64 gram / 16
n CH4 = 4 mol