f(x) = (x-2)(3x + 1), maka nilai f'(2) =

Bab Differensial
Matematika SMA kelas XI

f(x) = u . v
f'(x) = u' v + u v'

f(x) = (x - 2) (3x + 1)
f'(x) = 1 . (3x + 1) + (x - 2) . 3
f'(2) = (3 . 2 + 1) + (2 - 2) . 3
f'(2) = 7 + 0
f'(2) = 7

Turunan

f(x) = (x - 2)(3x + 1)
f(x) = 3x² + x - 6x - 2
f(x) = 3x² - 5x - 2

Turunannya
f'(x) = 6x - 5
f'(2) = 6(2) -5
f'(2) = 12-5
f'(2) = 7