Matematika

Pertanyaan

KUIS MATEMATIKA
Kode: 01-6-6
KUIS MATEMATIKA Kode: 01-6-6

2 Jawaban

  • Mapel : Matematika
    Kelas : VIII SMP
    Bab : Fungsi

    Pembahasan :
    f(1/2) = 12(1/2) - 5
    f(1/2) = 6 - 5
    f(1/2) = 1

    f(-1) = (-1)² + 2(-1) - 3
    f(-1) = 1 - 2 - 3
    f(-1) = -4

    f(2/3) = 12(2/3) - 5
    f(2/3) = 8 - 5
    f(2/3) = 3

    f(0) = 0² + 2(0) - 3
    f(0) = -3

    f(3/4) = 12(3/4) - 5
    f(3/4) = 9 - 5
    f(3/4) = 4

    f(1) = 12(1) - 5
    f(1) = 7

    Maka...
    f(1/2) . f(-1) + f(2/3) . f(0) + f(3/4) . f(1)
    = (1)(-4) + (3)(-3) + (4)(7)
    = - 4 - 9 + 28
    = 15

    Jawaban : C
  • Materi: Fungsi

    Pembahasan di gambar
    Gambar lampiran jawaban ShanedizzySukardi