jika g(×-2)=2×-3 dan (f o g )(×-2)=4×2-8×+3,maka f (-3)=

Komposisi Fungsi

g(x-2) = 2x - 3
fog(x-2) = 4x²  - 8x + 3
f{ g(x-2)} = 4x² -8x + 3
f (2x - 3) = 4x² - 8x + 3
f(3)= ...
2x - 3 = 3
2x = 6
x = 3

f(3) = 4(3)² - 8(3) + 3
f(3) = 36 - 24 +3
f(3) = 15