tolong pake caranya yaa

³log 1/5
= ³log (5^-1)
= -1 × ³log 5
= -1 × (log 5/log3)

a = ^5 log 6
b = ^6 log 3

maka

ab
= ^5 log 6 x ^6 log 3
= ^5 log 3

ab = log 3/log 5
ab . log 5 = log 3
1/ab = log5/log3

--->

= -1 × 1/ab
= - 1/ab

B

5log6 . 6log3 = 5log3
a . b = 5log3

3log(1/5) = 3log5^-1 = -1 . 3log5 = -1 . 1/(ab) = -1/(ab)