Ada yg bisa bantu? Thanks

log (2x + y) = 1
log (2x + y) = log 10
2x + y = 10
y = 10 - 2x

2^y = (2^2x)/4
2^y = (2^2x)/2^2
2^y = 2^(2x - 2)
y = 2x - 2 ==========> substitusi y = 10 - 2x
10 - 2x = 2x - 2
-2x - 2x = -2 - 10
-4x = -12
x = 3

y = 10 - 2x = 10 - 2(3) = 10 - 6 = 4

xy = 3 . 4 = 12