Ada yg bisa bantu? Thanks

Bab Logaritma
Matematika SMA Kelas X

log (64 (2^(x² - 40x))^(1/24)) = 0
64 (2^(x² - 40x)/24) = 1
2^((x² - 40x)/24) = 1/64
2^((x² - 40x)/24) = 2^-6
(x² - 40x)/24 = - 6
x² - 40x = 24 . (-6)
x² - 40x + 144 = 0
a = 1; b = -40; c = 144

hasil kali akar-akar = c/a
hasil kali akar-akar = 144/1
hasil kali akar-akar = 144

jawabannya A

log (64 . 2^(x^2 - 40x)/24) = 0
log (2^6 . 2^(x^2 - 40x)/24) = log 1
2^(6 + (x^2 - 40x)/24) = 1
2^(144 + x^2 - 40x)/24 = 2^0
(x^2 - 40x + 144)/24 = 0
x^2 - 40x + 144 = 0
(x - 36)(x - 4) = 0
x = 36 atau x = 4
Hasil kali = 36 . 4 = 144

ATAU

x1.x2 = c/a = 144/1 = 144