kak tolong jawab soal saya no 1-5 aja secepatnya dan benar ok jawaban terbaik menanti

1)
Dik :
mbesi=1 kg
Tbesi=100°C
mair=2 kg
Tair=20°C
Dit :
T=....?

Peny :
Qlepas=Qterima
mbesi . cbesi . ΔTbesi =mair . cair . ΔTair
1.450.(100-T)=2.4200.(T-20)
45000-450T=8400T-168000
8850T=213000
T=24,07°C

2)
Dik :
mpanas=100 gr
Tpanas=80°C
mdingin=200 gr
Tdingin=20°C
Dit :
T=....?

Peny :
Qlepas=Qterima
mpanas . cpanas . ΔTpanas =mdingin . cdingin . ΔTdingin
100 . (80-T) = 200 (T-20)
80-T = 2T-40
3T=120
T=40°C

3)
Dik :
mes=100 gr
Tes=0°C
mair=200 gr
Tair=20°C
Dit :
T=....?

Peny :
Qlepas=Qterima
mes L + mes . ces . ΔTes =mair . cair . ΔTair
100.80+100 . (T-0) = 200 (70-T)
8000+100T=200(70-T)
80+T=140-2T
3T=60
T=20°C

4)
Dik :
kp= 2 kq
tp=80°C
tq=20°C
Dit :
T=...?

Peny :
kp Δtp = kq Δtq
2kq (80-T) = kq (T-20)
160-2T=T-20
3T=180
T=60°C

Semoga Membantu

Nomor 1
-------------
Diket :
Massa besi, m1 = 1 kg
Suhu awal besi, T1 = 100°C
Massa air, m2 = 2 kg
Suhu awal air, T2 = 20°C
Kalor jenis besi, c1 = 450 J/kg°C
Kalor jenis air, c2 = 4200 J/kg°C

Tanya :
Suhu campuran, T = __?

Jawab :
Asas black
Q serap oleh air = Q lepas oleh besi

m2.c2.ΔT2 = m1.c1.ΔT1
2•4200•(T - 20) = 1•450•(100 - T)
840(T - 20) = 45•(100 - T)
168•(T - 20) = 9•(100 - T)
168/9•(T - 20) = (100 - T)
18,67•(T - 20) = 100 - T
18,67T - 373,4 = 100 - T
18,67T + T = 100 + 373,4
19,67T = 473,4
T = 473,4 / 19,67
T = 24,07°C

Nomor 2
-------------
Diket :
Massa air dingin, m1 = 200 gram
Suhu air dingin awal, T1 = 20°C
Massa air panas, m2 = 100 gram
Suhu air panas awal, T2 = 80°C

Tanya :
Suhu campuran, T = __?

Jawab :
Asas black
Q1 = Q2
m1.cair.ΔT1 = m2.cair.ΔT2
m1.ΔT1 = m2.ΔT2
200•(T - 20) = 100•(80 - T)
2•(T - 20) = (80 - T)
2T - 40 = 80 - T
3T = 120
T = 40°C

Nomor 3
-------------
Diket :
mes = 100 gram
Suhu es awal, Tes = 0°C
mair = 200 gram
Suhu awal air, Tair = 70°C
Kalor lebur es, Les = 80 kal/gram
Kalor jenis air, cair = 1 kal/gram.°C

Tanya :
Suhu campuran, T = __?

Jawab :
Q1 + Q2 = Q3
mes.Les + mes.cair.ΔTes = mair.cair.ΔTair

100•80 + 100•1•(T - 0) = 200•1•(70 - T)
80 + T = 2•(70 - T)
80 + T = 140 - 2T
3T = 60
T = 60/3
T = 20°C

Nomor 4
-------------
Diket :
Luas penampang sama, Ap = Aq
Panjang logam sama, Lp = Lq
Suhu logam P, Tp = 80°C
Suhu logam Q, Tq = 20°C

Konduktivitas logam P, Kp = 2.Kq

Tanya :
suhu sambungan, T = __?

Jawab :
Q/t logam P = Q/t logam Q
Kp.Ap.ΔT / Lp = Kq.Aq.ΔT / Lq
Kp.ΔT = Kq.ΔT
2•Kq•(80 - T) = Kq•(T - 20)
2•(80 - T) = T - 20
160 - 2T = T - 20
180 = 3T
T = 60°C

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FZA