Diketahui akar akar persamaan kuadrat x^2+px-3p+1=0adalah x1 dan x2 Jika x1^2+x2^2=5 maka nilai p =

x^2 + px - 3p + 1 = 0
x1 + x2 = -b/a = -p
x1 . x2 = c/a = -3p + 1

x1^2 + x2^2 = 5
(x1 + x2)^2 - 2x1.x2 = 5
(-p)^2 - 2(-3p + 1) = 5
p^2 + 6p - 2 = 5
p^2 + 6p - 7 = 0
(p - 1)(p + 7) = 0
p = 1 atau p = -7

Bab Persamaan Kuadrat
Matematika SMP Kelas VIII

x² + px - 3p + 1 = 0
a = 1; b = p; c = -3p + 1

x1² + x2² = 5
(x1 + x2)² - 2 x1 x2 = 5
(-b/a)² - 2 . c/a = 5
(-p/1)² - 2 . (-3p + 1)/1 = 5
p² + 6p - 2 - 5 = 0
p² + 6p - 7 = 0
(p + 7) (p - 1) = 0
p = -7 atau p = 1