diket f:R-R,g:R-R dgn (gof)(x) -4x^2+6x+1 dan f(x)=2x+3 maka g(-2)=

Fungsi Komposisi

(gof)(x) = g(f(x))

g(2x + 3) = - 4x² + 6x + 1
g(-2)?

Cari x

2x + 3 = -2
2x = -2-3
2x = -5
x = -5/2

Substitusi

g(-2)
= -4 . (-5/2)² + 6 . (-5/2) + 1
= - 4 . 25/4 + (-15) + 1
= -25 - 15 + 1
= -39

Mapel : Matematika
Kelas : X SMA
Bab : Fungsi

Pembahasan :
Gof(x) = -4x² + 6x + 1
G(f(x)) = -4x² + 6x + 1
G(2x + 3) = -4x² + 6x + 1
G(2x + 3) = -(2x + 3)² + 9(2x + 3) - 17
G(x) = -x² + 9x - 17
G(-2) = -(-2)² + 9(-2) - 17
G(-2) = -4 - 18 - 17
G(-2) = -39