Matematika

Pertanyaan

Mohon pakai jalannya
Mohon pakai jalannya

2 Jawaban

  • cara di atas ya semoga membantu
    Gambar lampiran jawaban Dhiyafairuz11
  • Luas ABCD = BC × AB
    120 = 10 × AB
    AB = 120 : 10
    AB = 12 cm

    AF = √(AB² + BF²)
    AF = √(12² + 5²)
    AF = √(144 + 25)
    AF = √(169)
    AF = 13 cm

    AD / FC = DE / CE
    10 / 5 = (DC + CE) / CE
    2CE = DC + CE
    2CE - CE = 12
    CE = 12 cm

    AE / FE = AD / FC
    (AF + FE) / FE = 10 / 5
    2FE = AF + FE
    2FE - FE = 13
    FE = 13 cm

    AE = AF + FE
    AE = 13 + 13
    AE = 26 cm

    Opsi D

    semoga berguna +_+