Jika diketahui f(x)=20x^3^1/2+2x^2^1/2+10x, maka f''(4) adalah

kalo ada soal kyk gni yg x tinffal diganti angka yg ada disebelah f aja

f(x)=20x^3^1/2+2x^2^1/2+10x
f(4) = 20 × 4^3^1/ + 2 × 4 ^2^1/2 + 10× 4

turunan
f(x) = 20 x⁷/²  + 2 x⁵/² + 10 x
f '(x)=  20(7/2) x⁵/² + 2 (5/2)x³/² + 10
f ' (x)= 70 x⁵/²  + 5 x³/²   + 10
f" (x) = 70 (5/2) x³/² + 5(3/2) x¹/²
f " (x) = 175 x³/²  + 15/2 x¹/²

f " (4) = 175 (4)³/² + 15/2 (4)¹/2
f " (4) = 175(8) + 15/2 (2) =
f "(4) = 1.415