tolong jawab pakai caranya...

1)
m = 0,5 Kg
∆T = Ta - 25°C
c = 900 J/Kg°C
Q = 2,25 kJ/Kg°C = 2.250 J/Kg°C

Q = m × c × ∆T
2.250 = 0,5 × 900 × (Ta - 25)
2.250 = 450 × (Ta -25)
(Ta - 25) = 2.250/450
(Ta - 25) = 5
Ta = 25 + 5
Ta = 30°C

2)
es = -25°X // 32°F
didih = 175°X // 212°F
air = 100°X // ?°F

(air - es)/(didih - es) = (air - es)/(didih - es)
(100 - (-25)/(175 - (-25) = (air - 32)/(212 - 32)
125/200 = (air - 32)/180
(air - 32) = 125 × 180/200
(air - 32) = 22.500/200
air = 112,5 + 32
air = 144,5°F