integral (x^3 -1/x^2)^2 dx

∫(x^3-x^-2)²dx
∫x^6- 2x^3-2 + x^-4→ x^6-2x+ x^-4
ingat ∫ax^n=1/n+1 x^n+1
= 1/7 x^7 - 2/2x^2 - 1/-3 x^-3
= 1/7 x^7 -x^2 + 1/ 3x^3