Jika 100ml hcl 0,02m d campur kan dengan 150 ml larutan HCl 0,02 m maka ph larutan terjadi adalah

[tex]\displaystyle KONSENTRASI \ CAMPURAN \ [XI] \\ \\ Mc = \frac{M1.v1+M2.v2}{v1+v2} \\ Mc = \frac{0,02.100+0,02.150}{100+150} \\ Mc = 0,02 \ M \\ \\
H^+ = M \ \times \ a = 0,02 \ \times \ 1 = 0,02 \ M \\
pH = - \ log \ H^+ \\
pH = - \ log \ 0,02 \\
pH = 2 \ - \ log \ 2 = 1,7 \xrightarrow \ Answer [/tex]

[HCl]1 = 0,02 M
V HCl 1 = 100 mL
[HCl]2 = 0,02 M
V HCl 2 = 100 mL

n HCl 1 = [HCl]1 × V HCl 1
= 0,02 M × 100 mL
= 2 mmol

n HCl 2 = [HCl]1 × V HCl 2
= 0,02 M × 150 mL
= 3 mmol

n HCl total = n HCl 1 + n HCl 2
= 2 mmol + 3 mmol
= 5 mmol

V total = V HCl 1 + V HCl 2
= 100 mL + 150 mL
= 250 mL

[HCl] total = n total / V total
= 5 mmol / 250 mL
= 0,02 M

pH = - log [H+]
= - log ( 0,02 )
= 2 - log 2