bantu dong hehee masih bingung aku sama soal ini 1. Jika diketahui f(x) = 4x dan f(g(x))=-x/2+1 maka nilai g(x) adalah... 2. Diketahui segitiga ABC siku-siku di

1. f(x) = 4x
f(g(x)) = -x/2 + 1
=> f(g(x)) = -x/2 + 1
=> 4(g(x)) = -x/2 + 1
=> g(x) = (-x/2 + 1)/4
=> g(x) = (-x + 2)/8

1) f(g(x)) = -x/2 + 1
4g(x) = -1/2 x + 1
g(x) = -1/8 x + 1/4
g(x) = (-x + 2)/8

2) siku-siku di B => sisi miringnya = AC
sudut BAC = 30°,
BC = 4 cm => sisi depan
Sin BAC = depan/miring
Sin 30° = BC/AC
1/2 = 4/AC
AC = 8
AB = √(AC^2 - BC^2) = √(8^2 - 4^2) = √(64 - 16) = √48 = 4√3
AB + AC = (4√3 + 8) cm = 4(√3 + 2) cm

3) A + B + C = 180°
105° + 30° + C = 180°
C = 45°
AB/(sin C) = AC/(sin B)
AB/(sin 45°) = (5√2)/(sin 30°)
AB/(1/2 √2) = (5√2)/(1/2)
AB = (1/2 √2 . 5√2) / (1/2) = 10 cm