Tentukan nilai (a+b) x (a-b) + (a:b) jika (pada gambar)

[tex]\frac { a }{ b } +2=3\\ \frac { a }{ b } =3-2\\ \frac { a }{ b } =1\\ a=b[/tex]
Sehingga kita dapatkan 
[tex](a+b)(a-b)+\frac { a }{ b } ={ a }^{ 2 }-{ b }^{ 2 }+\frac { a }{ b } \\ (a+b)(a-b)+\frac { a }{ b } =0+1\\ (a+b)(a-b)+\frac { a }{ b } =1[/tex]

a/b + 2 = 3
a/b = 3 - 2
a/b = 1
a = b

a + 2/5b = 7/5
b + 2/5b = 7/5
7/5b = 7/5
b =1
a = 1

a+b = 1 +1 = 2
a-b = 1-1 = 0
a/b = 1

maka
(a+b) x (a-b) + (a:b) =2 x 0 + 1 = 1