Hasil dari a^-2b + ab^-2 per a^-1 + b^-1 =
Matematika
nikeneria
Pertanyaan
Hasil dari a^-2b + ab^-2 per a^-1 + b^-1 =
1 Jawaban
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1. Jawaban arsetpopeye
(a^-2b + ab^-2) / (a^-1 + b^-1)
= (b/a^2 + a/b^2) / (1/a + 1/b)
= (b^3 + a^3)/(a^2.b^2) / (b + a)/(ab)
= (b^3 + a^3)/(ab)^2 . (ab)/(b + a)
= (b^3 + a^3) / (ab)(b + a)
= ((b + a)^3 - 3ab(b + a)) / (ab)(b + a)
= (b + a) ((b + a)^2 - 3ab) / (ab)(b + a)
= ((a + b) - 3ab) / ab