14.persamaan garis yg melalui titik P(-2,6) dan tegak lurus garis -3x+2y-12=0 adalah

-3x + 2y - 12 = 0 => m = -a/b = -(-3)/2 = 3/2
Karena tegak lurus m = -2/3 ===> (m1 . m2 = -1)

Persamaan garis melalui (-2, 6) dan m = -2/3
y - y1 = m(x - x1)
y - 6 = -2/3 (x - (-2))
3(y - 6) = -2(x + 2)
3y - 18 = -2x - 4
2x + 3y - 14 = 0

2x + 3y = 14

-3x + 2y - 12 = 0
2y = 3x + 12
y = 3/2 x + 6

m1 = 3/2
karna tegak lurus maka
m1.m2 = -1
m2 = -1 × ⅔
m2 = - ⅔

Persamaan Garis →
y - y1 = m2 (x - x1)
y - 6 = - ⅔ (x + 2) ------- (×3)
3y - 18 = -2x - 4
2x + 3y - 14 = 0

semoga berguna +_+