1.luas=154 cm2 keliling=............cm jari-jari=.........cm diameter=......cm (cara darimana dapat hasil kel,jari jari,diameter) TOLONG YA JAWABANNYA PENTING B
Matematika
David29stg
Pertanyaan
1.luas=154 cm2
keliling=............cm
jari-jari=.........cm
diameter=......cm
(cara darimana dapat hasil kel,jari jari,diameter)
TOLONG YA JAWABANNYA PENTING BANGET
keliling=............cm
jari-jari=.........cm
diameter=......cm
(cara darimana dapat hasil kel,jari jari,diameter)
TOLONG YA JAWABANNYA PENTING BANGET
2 Jawaban
-
1. Jawaban reniendi
luas bangun apa?lingkaran?
luas lingkaran = [tex] \pi r^{2} [/tex]
154 = 22/7 [tex] r^{2} [/tex]
[tex] r^{2} [/tex] = 154 * 22/7
[tex] r^{2} [/tex] = 484
r = [tex] \sqrt{484} [/tex]
r = jari-jari = 22 cm
keliling = [tex] \pi [/tex]2r
= 22/7*2*22
= 138,28 cm
diameter = 2r
= 2*22=44 cm -
2. Jawaban aidilzulhaq
154 = 22/7 r kuadrat
154 / 22 = 1/7 r kuadrat
7 x 7 = r kuadrat
7 cm = r
k = 2 phi r
k = 2 x 22/7 x 7
k = 44 cm
d = 2 r
d = 14