kak tolong jwab soal no 2 dong,cuma tinggal no 2 aja

a) AC = √(13^2 - 5^2) = √(169 - 25) = √144 = 12
b) sin a = AC/BC = 12/13
c) cos a = AB/BC = 5/13
d) Tan a = AC/AB = 12/5
e) cosec B = BC/AB = 13/5
f) sec B = BC/AC = 13/12
g) cot B = AC/AB = 12/5