Matematika

Pertanyaan

tolong di bantu...... udah mau di kumpul nih :-|
tolong di bantu...... udah mau di kumpul nih :-|

1 Jawaban

  • a.
    sin 1/2 x = sin π/4

    1/2 x = π/4 + k.2π
    x = π/2 + k.4π
    k = 0,x= π/2
    k=1,x =9π/2 (t.m)

    1/2 x = 3π/4 + k.2π
    x = 3π/2 + k.4π
    k=0,x=3π/2
    k=1,x =11π/2 (t.m)

    HP = {π/2 , 11π/2}

    2.
    sin (x - π) = sin π/3

    x - π = π/3 + k.2π
    x = 4π/3 + k.2π
    k=0,x=π/3

    x - π = 2π/3 + k.2π
    x = 5π/3 + k.2π
    k=0,x=5π/3

    HP = {π/3 , 5π/3}


    c.
    sin 3x= cos x
    sin 3x = sin (π/2 - x)

    3x = π/2 - x + k.2π
    4x =  π/2 + k.2π
    x = π/8 + k.π/2
    k=0,x=π/8
    k=1, x = 5π/8

    HP = {π/8 , 5π/8}

    d.
    cos 2x = cos 40

    2x = 40 + k.360
    x = 20 + k.180
    k =0,x = 20°
    k=1,x = 200°


    2x = -40 + k.360
    x = -20 + k.180
    k=1, x = 160°
    k=2,x = 340°

    HP = {20°,160°,200°,340°}

    e.
    cos 2x = cos x

    2x = x + k.360
    x = k.360
    k=0,x=
    k=1,x = 360°

    2x = -x + k.360
    3x = k.360
    x = k.120
    k=1,x=120°
    k=2,x =240°

    HP = {0°,120°,240°,360°}

    f.
    cos 2x = sin x
    cos 2x = cos (90 - x)

    2x = 90 - x + k.360
    3x = 90 + k.360
    x = 30 + k.120
    k=0,x=30°
    k=1,x = 150°
    k=2,x = 270°

    2x = -90 + x + k..360
    x = -90 +k.360
    k=1,x=270°

    HP={30°,150°,270°}

    g.
    tan 2x = tan 20

    2x = 20 + k.180
    x = 10 + k.90
    k =0,x=10°
    k=1,x =100°

    Hp={10° , 100°}
    h.
    tan 2x = tan π

    2x = π + k.π
    x = π/2 + k.π/2
    k=0,x = π/2
    k=1,x= π


    Hp= {π/2 , π}

    i.
    tan 3x = cot x
    tan 3x = tan (π/2 - x)

    3x = π/2 - x + k.π
    4x = π/2 + k.π
    x = π/8 + k.π/4
    k=0,x=π/8
    k=1,x=3π/8
    k=2,x = 5π/8


    Hp= {π/8 , 3π/8 , 5π/8}