tolong di bantu...... udah mau di kumpul nih :-|
Matematika
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Pertanyaan
tolong di bantu...... udah mau di kumpul nih :-|
1 Jawaban
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1. Jawaban 18Navillera
a.
sin 1/2 x = sin π/4
↓
1/2 x = π/4 + k.2π
x = π/2 + k.4π
k = 0,x= π/2
k=1,x =9π/2 (t.m)
1/2 x = 3π/4 + k.2π
x = 3π/2 + k.4π
k=0,x=3π/2
k=1,x =11π/2 (t.m)
HP = {π/2 , 11π/2}
2.
sin (x - π) = sin π/3
↓
x - π = π/3 + k.2π
x = 4π/3 + k.2π
k=0,x=π/3
x - π = 2π/3 + k.2π
x = 5π/3 + k.2π
k=0,x=5π/3
HP = {π/3 , 5π/3}
c.
sin 3x= cos x
sin 3x = sin (π/2 - x)
↓
3x = π/2 - x + k.2π
4x = π/2 + k.2π
x = π/8 + k.π/2
k=0,x=π/8
k=1, x = 5π/8
HP = {π/8 , 5π/8}
d.
cos 2x = cos 40
↓
2x = 40 + k.360
x = 20 + k.180
k =0,x = 20°
k=1,x = 200°
2x = -40 + k.360
x = -20 + k.180
k=1, x = 160°
k=2,x = 340°
HP = {20°,160°,200°,340°}
e.
cos 2x = cos x
↓
2x = x + k.360
x = k.360
k=0,x= 0°
k=1,x = 360°
2x = -x + k.360
3x = k.360
x = k.120
k=1,x=120°
k=2,x =240°
HP = {0°,120°,240°,360°}
f.
cos 2x = sin x
cos 2x = cos (90 - x)
↓
2x = 90 - x + k.360
3x = 90 + k.360
x = 30 + k.120
k=0,x=30°
k=1,x = 150°
k=2,x = 270°
2x = -90 + x + k..360
x = -90 +k.360
k=1,x=270°
HP={30°,150°,270°}
g.
tan 2x = tan 20
↓
2x = 20 + k.180
x = 10 + k.90
k =0,x=10°
k=1,x =100°
Hp={10° , 100°}
h.
tan 2x = tan π
↓
2x = π + k.π
x = π/2 + k.π/2
k=0,x = π/2
k=1,x= π
Hp= {π/2 , π}
i.
tan 3x = cot x
tan 3x = tan (π/2 - x)
↓
3x = π/2 - x + k.π
4x = π/2 + k.π
x = π/8 + k.π/4
k=0,x=π/8
k=1,x=3π/8
k=2,x = 5π/8
Hp= {π/8 , 3π/8 , 5π/8}