Tolong dijawab no 33 dan 34 ya kaa

33) 2^(x + 1) + 1/(2^(x - 3)) = 17
2^x . 2 + 1/(2^x . 2^-3) = 17
2 . 2^x + 2^3 / 2^x = 17
Misal 2^x = p
2p + 8/p = 17 ===> kedua ruas kali p
2p^2 + 8 = 17p
2p^2 - 17p + 8 = 0
(2p - 1)(p - 8) = 0
p = 1/2 atau p = 8
2^x = 2^-1 atau 2^x = 2^3
x = -1 atau x = 3
Jadi x1^2 + x2^2 = (-1)^2 + 3^2 = 1 + 9 = 10

34) Misal : a x a x a x a = a^4 karena a nya sebanyak 4 jadi
Karena 25^(0,25) nya sebanyak n maka

25^(0,25) x 25^(0,25) x .... x 25^(0,25) = 125
(25^(0,25))^n = 125
25^0,25n = 125
(5^2)^(0,25n) = 5^3
5^(0,5n) = 5^3
0,5n = 3
1/2 n = 3
n = 6
(n - 3)(n + 2) = (6 - 3)(6 + 2) = (3)(8) = 24