Tolong pakai cara terimakasih
Matematika
Anonyme
Pertanyaan
Tolong pakai cara terimakasih
1 Jawaban
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1. Jawaban BeetSha
1)
[tex]( \frac{ x^{2} }{y ^{-4} }) ^{2} .( \frac{y ^{-3} }{ x^{2} } ) ^{3} \\ =( x^{2} y ^{4}) ^{2} . (\frac{1}{ x^{2} y ^{3} }) ^{3} \\ = x^{4} y ^{8}. \frac{1}{ x^{6}y ^{9} } \\ = \frac{ x^{4}y ^{8} }{ x^{6} y ^{9} } \\ =\frac{1}{ x^{2} y} \\ = x^{-2} y ^{-1} [/tex]
2)
[tex]( \frac{p ^{-3}q ^{4} }{r ^{-2}s ^{3} } ) ^{2} . (\frac{p ^{3}r ^{-3} }{q ^{-4}s ^{4} } ) ^{-2} \\= ( \frac{r ^{2}q ^{4} }{p ^{3}s ^{3} } ) ^{2}. ( \frac{p ^{-3}r ^{3} }{q ^{4} s ^{-4} } ) ^{2} \\ = \frac{r ^{4}q ^{8} }{p ^{6}s ^{6} } .( \frac{s ^{4}r ^{3} }{p ^{3}q ^{4} }) ^{2} \\ = \frac{r ^{4}q ^{8} }{p ^{6}s ^{6} } . \frac{s ^{8}r ^{6} }{p ^{6}q ^{8} } \\ = \frac{r ^{10}q ^{8}s ^{8} }{p ^{12}q ^{8} s ^{6} } \\ = \frac{r ^{10} s ^{2} }{p ^{12} } [/tex]