Mohon bantuannya yah

Saya coba bantu jawab yah !

Penyelesaian :
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Diket : f (x) = 1/2x - 1 , g (x) = 2x + 4

Pertama, kita cari dulu fungsi gof (x)

gof (x) = g {f (x)}
gof (x) = g (1/2x - 1)
gof (x)= 2 (1/2x - 1) + 4
gof (x) = x - 2 + 4
gof (x) = x + 2

Maka,
gof (x) = x + 2
y = x + 2
x = y - 2
gof⁻¹ (x) = x - 2

Sehingga ,
gof ⁻¹ (10)
= x - 2
= 10 - 2
= 8

Jawabannya = 8

Semoga bisa membantu

Mapel : Matematika
Kelas : X SMA
Bab : Fungsi

Rumus Cepat :
f(x) = ax + b
f¯¹(x) = (x - b)/a

Pembahasan :
Gof(x) = g(f(x))
Gof(x) = 2(1/2x - 1) + 4
Gof(x) = x + 2
Gof¯¹(x) = x - 2
Gof¯¹(10) = 10 - 2
Gof¯¹(10) = 8