bantu jawab plis,buat besok
Matematika
indiraamara
Pertanyaan
bantu jawab plis,buat besok
2 Jawaban
-
1. Jawaban 18Navillera
a.
AE/AC = AD/AB
AE/(5 + AE) = 5/(5 + 4)
9AE = 25 + 5AE
4AE = 25
AE = 6,25
b.
A
AC = 6,25 + 5
AC = 11,25
c.
DE/BC = AD/AB
6/BC = 5/9
54 = 5BC
BC = 10,8 -
2. Jawaban BeetSha
Rumus:
[tex] \frac{AD}{AB} = \frac{AE}{AC} = \frac{DE}{BC} [/tex]
a) Panjang AE
[tex] \frac{AD}{AB}= \frac{AE}{AC} \\ \frac{5}{5+4} = \frac{AE}{AE+5} \\ \frac{5}{9}= \frac{AE}{AE+5} \\ 9(AE)=5(AE+5) \\ 9AE =5AE+25 \\ 9AE-5AE=25 \\ 4AE=25 \\ AE= \frac{25}{4} [/tex]
AE = 6,25 cm
b) Panjang AC
AC = AE + EC
AC = 6,25 + 5
AC = 11,25 cm
c) Panjang BC
[tex] \frac{AD}{AB}= \frac{DE}{BC} \\ \frac{5}{5+4}= \frac{6}{BC} \\ \frac{5}{9} = \frac{6}{BC} \\ 5(BC)=(9)(6) \\ 5BC=54 \\ BC= \frac{54}{5} [/tex]
BC = 10,8 cm