Bantuin dong please:
Matematika
Amndaay
Pertanyaan
Bantuin dong please:"
1 Jawaban
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1. Jawaban Sutr1sn0
1]
a = 32
b = 27
[4a^(-2/5)]×[5b^(1/3)]
= [4(32)^(-2/5)]×[5(27)^(1/3)]
= [4(2^5)^(-2/5)]×[5(3^3)^(1/3)]
= [4(2)^(-2)]×[5(3)]
= [2^2.2^(-2)]×15
= [2^0]×15
= 1×15
= 15
2] a^(-2) b^8 c^(-10)
....---------------------------
......a^12 b^(-4) c^6
= a^(-2-12) b^(8-(-4)) c^(-10-6)
= a^(-14) b^12 c^(-16)
...........b^12
= ------------------
........a^14 c^16
3]
......27×3^(-2)×3
.....-------------------
.........81×9^(-2)
........3^3×3^(-2)×3
....= ------------------------
...........3^4×(3^2)^(-2)
........3^2
= ---------------
.....3^4×3^(-4)
...........3^2
= ---------------
...........3^0
= (3^2)/1
= 3^2
= 9