Kakak dan teman teman ataupun Ade ade bantuin aku ngerjain PR ini ya aku kesulitan

a.
[tex] \frac{AE}{5}= \frac{AE+5}{5+4} [/tex]
9AE = 5(AE+5)
9AE = 5AE + 25
9AE-5AE = 25
4AE = 25
AE = 25/4
AE = 6,25

b.
AC = AE + EC
AC = 6,25 + 5
AC = 11,25

c.
5 / 6 = (5+4) / BC
5/6 = 9/BC
5BC = 9 X 6
5BC = 54
BC = 54 / 5
BC = 10,8

A.panjang AE/AD=AC/AB
AE/5=AE+5/ 9
9AE= 5AE+25
4AE= 25
AE=25/4= 6,25

B.AC= 5+25/4 =5+6,25= 11,25

c.Panjang BC/AB== DE/AD
BC/9= 6/5
= 54/5

semoga membantu :)