tolong nmr 5sampe 7 yaa
Matematika
KurooBakStun
Pertanyaan
tolong nmr 5sampe 7 yaa
1 Jawaban
-
1. Jawaban Milieth
5)
a)
9p×5p²×4pq=45p³×4pq
=180p⁴q
b)
3x×6x²y×(-4xy²)=18x³y×(-4xy²)
=-72x⁴y³
c)
p²q³r÷pq²r=[tex] \frac{p^{2}q^{3}r }{pq^{2}r} [/tex]
=pq
d)
24xy³z²÷xy²z=[tex] \frac{24xy^{3}z^{2}}{xy^{2}z} [/tex]
=24yz
6)
a)
2×3²=2×9
=18
b)3⁴×3²=3⁽⁴⁺²⁾
=3⁶
=729
c)
5⁷:5³=5⁽⁷⁻³⁾
=5⁴
=625
d)
2⁴×3×2³=3×2⁽⁴⁺³⁾
=3×2⁷
=3×128
=384
7)
a)
(2³)²=2³ˣ²
=2⁶
=64
b)
[tex](\frac{2}{5})^{4}[/tex]=[tex]\frac{2^{4}}{5^{4}}[/tex]
=[tex]\frac{16}{625}[/tex]
c)
(3²×3)²=(3³)²
=3⁶
=729
d)
[tex]( \frac{-4}{5} )^{4}[/tex]=[tex]\frac{-4^{4}}{5^{4}}[/tex]
=[tex]\frac{256}{625}[/tex]