Matematika

Pertanyaan

Sederhanakanlah
1- 1/b^2 x 2y^7 x b^3 x y^-3
2-3m^3 x (2mn)^4
3-(tn^3)^4 x 4t^2
4- akar kuadrat dari 4 21/25

1 Jawaban

  • 1/b^2 × 2y^7 × b^3 × y^-3
    = b^(3-2) × 2y^(7+(-3))
    = 2by^4

    3m^3 × (2mn)^4
    = 3m^3 × 2^4 × m^4 × n^4
    = 48m^7 . n^4

    (tn^3)^4 × 4t^2
    = 4t^(4+2) × n^12
    = 4t^6 . n^12

    √(4 21/25)
    = √(4 + 21/25)
    = √((100 + 21)/25)
    = √(121/25)
    = 11/5
    = 2 1/5

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