Matematika

Pertanyaan

Please kak tlong ya berapa persamaan trogonometrinya kak kalau
Tan (x-60)+1/3√3=0
k= 0,1,2,3,4,....

2 Jawaban

  • Tan (x - 60°) + 1/3 √3 = 0
    Tan (x - 60°) = -1/3 √3
    Tan (x - 60°) = Tan 150°
    x - 60° = 150° + k . 180°
    x = 210° + k . 180°
    k = 0 => x = 210°
    k = 1 => x = 390°
    Jadi x = 210°
  • tan (x - 60) + 1/3 √3 = 0
    tan (x - 60) = -1/3 √3
    tan (x - 60) = tan (-30)

    x - 60 = -30 + k.180
    x = 30 + k.180
    k= 0,x = 30°
    k=1,x=210°

    HP= {30°,210°}

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