Please kak tlong ya berapa persamaan trogonometrinya kak kalau Tan (x-60)+1/3√3=0 k= 0,1,2,3,4,....
Matematika
Naufal1805
Pertanyaan
Please kak tlong ya berapa persamaan trogonometrinya kak kalau
Tan (x-60)+1/3√3=0
k= 0,1,2,3,4,....
Tan (x-60)+1/3√3=0
k= 0,1,2,3,4,....
2 Jawaban
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1. Jawaban arsetpopeye
Tan (x - 60°) + 1/3 √3 = 0
Tan (x - 60°) = -1/3 √3
Tan (x - 60°) = Tan 150°
x - 60° = 150° + k . 180°
x = 210° + k . 180°
k = 0 => x = 210°
k = 1 => x = 390°
Jadi x = 210° -
2. Jawaban 18Navillera
tan (x - 60) + 1/3 √3 = 0
tan (x - 60) = -1/3 √3
tan (x - 60) = tan (-30)
x - 60 = -30 + k.180
x = 30 + k.180
k= 0,x = 30°
k=1,x=210°
HP= {30°,210°}