Soal tentang vektor!

1. diketahui
F1 = 6
F2 = 8
a. Searah
Resultan = F1+F2 = 6 + 8 = 14

b. Berlawanan arah
Resultan = √(F1^2 + F2^2 + 2F1F2 cos 180)
Resultan = √(36 + 64 + 2.6.8.(-1))
Resultan = √4
Resultan = 2

c. jika sudut=90 derajat
Resultan = √(F1^2 + F2^2 + 2F1F2 cos 90)
Resultan = √(36 + 64 + 2.6.8.0)
Resultan = √100
Resultan = 10

2. diket
F1= 20 N
F2 = 40 N
Sudut = 120 derajat

Selisih = √(20^2 + 40^2 + 2.20.40 cos (180-120))
Selisih = √(400 + 1600 + 1600 cos (60))
Selisih = √(2800)
Selish = 20√7