Matematika

Pertanyaan

tentukan integral tak tentu,,,
tentukan integral tak tentu,,,

1 Jawaban

  • (sin x + cos x)² = 1 + 2 sinx cos x = 1 + sin 2x

    dcos 2x /dx = -2sin 2x
    sin 2x dx = (-1/2)dcos 2x

    Int (sin x + cos x)² dx
    = Int (1 + sin 2x) dx
    = Int 1 dx + Int sin 2x dx
    = x + Int (-1/2)dcos 2x
    = x - (1/2)cos 2x + C