Persamaan sumbu simetri y=4(x+2)(x-1) adalah

Bab Persamaan Kuadrat
Matematika SMP Kelas VIII

y = 4 (x + 2) (x - 1)
y = 4 (x² + x - 2)
y = 4x² + 4x - 8
a = 4; b = 4; c = -8

sumbu simetri = -b/2a
sumbu simetri = -4/(2 . 4)
sumbu simetri = -1/2

y = 4 (x + 2) (x - 1)
y = 4 {(x+2)(x-1)}
y = 4 (x^2+2x-x-2)
y = 4 (x^2 + x - 2)
y = 4x^2 + 4x - 8

a = 4
b = 4
c = -8

sb. simetri = -b/2a
= -4/(2.4)
= -4/8
= -1/2