tentukan hasil operasi hitung bentuk aljabar berikut. 1. (a+1)²+(a²-7a+1) 2. (-x²+8x-5)-(3x²-6x+7) plis tulis jalan nya ya..

1. (a+1)²+(a²-7a+1)
  =(a2+2a+1)+(a2-7a+1)
=a2+2a+1+a2-7a+1
=2a²-5a+2

2.(-x²+8x-5)-(3x²-6x+7)
=-x2+8x-5-3x2+6x-7
=-4x2+14x-12

terima kasih

1. (a+1)^2+(a^2-7a+1)
=2a+1+a^2-7a+1
=a^2+2a-7a+1+1
=a^2-5a+2

2.(-x^2+8x-5)-(3x^2-6x+7)
=-x^2+8x-5-3x^2-6x+7
=-x^2-3x^2+8x-6x-5+7
=-4x+2x-2

semoga membantu :)